MCQsLlearn App Download MCQsLearn Free App
As an Amazon Associate I earn from qualifying purchases.

O Level Online Exam Test MCQ Questions with Answers PDF Download eBook

Practice O Level Online Exam Test Multiple Choice Questions (MCQ), o level online exam test quiz answers PDF worksheet, O level physics test for online college programs. Solve kinetic theory of particles Multiple Choice Questions and Answers (MCQs), "O Level Online Exam Test" quiz questions and answers for online degree programs. Learn kinetic theory of particles test prep for ACT subject test tutoring.

"If the car tires are hot, the pressure of gas molecules in them would be" Multiple Choice Questions (MCQ) on o level online exam test with choices high, low, same as before heating, and may be high or low for online degree programs. Solve o level online exam test quiz questions for merit scholarship test and certificate programs for best online SAT prep class. O Level Online Exam Test Video

MCQs on O Level Online Exam Test PDF Download eBook

MCQ: If the car tires are hot, the pressure of gas molecules in them would be

  1. high
  2. low
  3. same as before heating
  4. may be high or low

A

MCQ: Volume of gas is

  1. directly proportional to temperature
  2. inversely proportional to temperature
  3. directly proportional to friction
  4. inversely proportional to heat

A

MCQ: If air at a pressure of 1 MPa is compressed such that the new volume of the air is one quarter of its initial volume, then the new pressure of the air is

  1. 1 M Pa
  2. 0.25 M Pa
  3. 2 M Pa
  4. 4 M Pa

D

MCQ: In an aquarium, air bubble at the bottom has a volume = 0.5 mm³. What would be the size of the bubble at the top if the height of the water level is = 1 m. (density of water = 1000 kg ⁄ m³, atmospheric pressure = 1 × 105 Pa, gravitational acceleration = 10 m s-1²)

  1. 0.5 mm³
  2. 0.55 mm³
  3. 0.6 mm³
  4. 0.65 mm³

B

MCQ: As the volume is inversely proportional to pressure, we can conclude that

  1. p1V2 = p2V1
  2. p2/V2 = p1V1
  3. p1V1 = p2V2
  4. p1V1 = p2/V2

C