# Vector Addition by Rectangular Components MCQs Quiz Online PDF Download eBook

Vector Addition by Rectangular Components Multiple Choice Questions (MCQ), vector addition by rectangular components quiz answers PDF to practice online physics test for online classes. Learn vector and equilibrium Multiple Choice Questions and Answers (MCQs), "Vector Addition by Rectangular Components" quiz questions and answers for completely online college. Learn magnitude of a vector, cross product of two vectors, vectors in physics, applied physics: vectors test prep for college entrance exams.

"Direction of the resultant of two vectors is given by" Multiple Choice Questions (MCQ) on vector addition by rectangular components with choices *cos ^{-1}(a_{y} + b_{y}/a_{x} + b_{x}), cos^{-1}(a_{x} + b_{y}/a_{y} + b_{x}), tan^{-1}(a_{y} + b_{y}/a_{x} + b_{x}), and tan^{-1}(a_{y} - b_{y}/a_{x} - b_{x})* for completely online college. Practice merit scholarships assessment test, online learning vector addition by rectangular components quiz questions for competitive exams in physics majors for best online colleges for teaching degree. Vector Addition by Rectangular Components Video

## MCQs on Vector Addition by Rectangular Components PDF Download eBook

MCQ: Direction of the resultant of two vectors is given by

- cos
^{-1}(A_{y}+ B_{y}/A_{x}+ B_{x}) - cos
^{-1}(A_{x}+ B_{y}/A_{y}+ B_{x}) - tan
^{-1}(A_{y}+ B_{y}/A_{x}+ B_{x}) - tan
^{-1}(A_{y}- B_{y}/A_{x}- B_{x})

C

MCQ: Vector's x-components are represented by the formula of

- A
_{x}+ B_{x} - A
_{x}+ B_{y} - A
_{x}- B_{x} - A
_{x}- B_{y}

A

MCQ: The y-components of the vectors are represented by the formula of

- A
_{y}+ B_{y} - A
_{y}- B_{y} - A
_{y}+ B_{x} - A
_{y}- B_{x}

A

MCQ: The x-components of the vectors are represented by the

- subtraction of x-components
- subtraction of y-components
- sum of x-components
- sum of y-components

C

MCQ: Resultant magnitude of two vectors is given by the formula

- √((A
_{x}+ B_{x})² + (A_{y}+ B_{y})²) - √((Ax + By) + (Ay + Bx))
- √((Ax + Bx)-(Ay + By))
- √((Ax-Bx) + (Ay-By))

A