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MCQ 1109: Consider the reaction: Al2O3 + NaOH + H2O(l) → NaAl(OH)4(aq). Moles of NaAl(OH)4(aq) produced with 1 mole of Al2O3 will be:

  1. 1
  2. 2
  3. 3
  4. 4
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