Electronic Engineering

Digital Electronics MCQs

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Complex Gate MCQ with Answers

Complex Gate Multiple Choice Questions (MCQ) to practice complex gate quiz answers PDF, complex gate worksheets for online degrees. Solve cmos logic gates circuits Multiple Choice Questions and Answers (MCQs), "Complex Gate Quiz Questions" and answers to learn free online courses. Learn cmos nand gate, complex gate, cmos exclusive or gate test prep for tricky trivia questions.

"By De Morgan's Law Y=bar(A)+bar(B+CD) is equals to" Multiple Choice Questions (MCQ) on complex gate with choices bar(a)bar(b+cd), bar(a)+bar(b)(cd), bar(a)+bar(b)bar(cd), and bar(a)bar(b)bar(cd) to learn free online courses. Solve complex gate quiz questions for merit scholarship test and certificate programs to learn free online courses.

MCQs on Complex Gate

1.

By De Morgan's Law Y=bar(A)+bar(B+CD) is equals to

bar(A)bar(B+CD)
bar(A)+bar(B)(CD)
bar(A)+bar(B)bar(CD)
bar(A)bar(B)bar(CD)

2.

By DE Morgan's Law Y=bar(A(B+CD)) is equals to

bar(A)bar(B+CD)
bar(A)+bar(B+CD)
A+bar(B+CD)
bar(A)+(B+CD)

3.

System in which Y is high for A input is high and simultaneously either B input is high or C and D both are high is represented as

Y=A(B+CD)
bar(Y)=A(B+CD)
bar(Y)=A(2+CD)
bar(Y)=AB+CD

4.

By De Morgan's Law Y=bar(A)+bar(B)bar(CD) is equals to

bar(A)bar(B+CD)
bar(A)+bar(B)(bar(C)+D)
bar(A)+bar(B)(C+D)
bar(A)+bar(B)(bar(C)+bar(D))

5.

System in which Y will be high if A is low or B and C are both low is represented as

Y=A+BC
Y=ABC
Y=A+bar(BC)
Y=bar(A)+bar(BC)